Wahl zwischen FF8 und FF9

[Icetongue]

Das Kartenspiel ist zufällig wie sonst was. Wenn ich in FF8 eine 9 an eine 7 lege, weiss ich dass die Karte gewinnt. In FF9 kommen Statuswerte, Elemente und der Zufall dazu.

Cards will have a few stats below the picture. Here's what they mean:

PTDM
----
P : the power of the card in hexadecimal.
T : the card type, P, M, X, or A.
D : the card's physical defense in hexadecimal.
M : the card's magical defense in hexadecimal.

Example: 1P40

What is hexadecimal, you ask? Hexadecimal is the numbers represented
from 0-15 by letters and numbers. So 0 is 0, and 15 is F. This means
the strongest card in the game would be FAFF, since A is the strongest
card type.

Here's the confusing part. While the card's stats are represented in
hex, those stats represent another number entirely. Here's a chart.

Hex | Stat | Min | Max
-------------------------
0F | 0 | 000 | 015
1F | 1 | 016 | 031
2F | 2 | 032 | 047
3F | 3 | 048 | 063
4F | 4 | 064 | 079
5F | 5 | 080 | 095
6F | 6 | 096 | 111
7F | 7 | 112 | 127
8F | 8 | 128 | 143
9F | 9 | 144 | 159
AF | A | 160 | 175
BF | B | 176 | 191
CF | C | 192 | 207
DF | D | 208 | 223
EF | E | 224 | 239
FF | F | 240 | 255

Why the "Hex" column? Notice how the first number in the hex
column matches the number in the stat column? That's how hexadecimal
works. For a two digit hex number, you take the first number,
multiply by 16 and add the value of the second number. So 6F is
6*16+15 = 111. The minimum value would be 60 or 6*16+0=96.


Phase 1:
* Each card has a power as discussed previously. This value falls
between the min and max listed in the table. Each card also has
a defense fitting the the above chart.

A B
Example : 4P22 attacks 1M01

The first number that appears on card A is its attack power, say
70 (4 = between 64 and 79). Card A is a physical card, and card
B has 0 physical defense, so the first number to appear on card
B is its defense, say 7 (0 = between 0 and 16).

Phase 2:
# Next, the computer rolls a number between 0 and the number shown
in phase 1. This will be the *actual* attack or defense. Let's
say it rolls a 66 for card A, and 1 for card B.

Phase 3:
# The number rolled in phase 2 is subtracted from the number in
phase 1. This guarantees that the number will be positive, and
the highest number wins. So:

Card A: 70 - 66 : 4
Card B: 7 - 1 : 6

There are a few things this should tell you :

1.) Higher rolls are BAD. You want low rolls so less is subtracted
from the total number.
2.) A weak card can defeat a strong card if the roll is in its favor,
look at how the 1M01 defended itself against a 4P22. <--- genau sowas passiert mir in 50% aller Fälle und ich sehe nicht ein, wo ein derartiger Zufall seinen Platz hat.

If you want to know how likely a card is to win a battle, here's the
basic formula:

1 + Power of Weak
100 * (1 - ----------------------)
2*(1+ Power of Strong)

So in our example, you have:

1 + 7 142 - 8 136
100 * ( 1 - --------- ) = 100 * --- --- = 100 * --- = 94.4%
2(1 + 70) 142 142 142

So in our example, card A will win the battle 94% of the time. But
in the example of the battle, it lost because of a bad roll; that's
the 6% it loses.

But, since you may not know attack/defense values right away, you
can get a basic idea. Using our example again, take the maximum
attack card A could have (79) and the lowest defense card B can have
(0) and use our equation. The result is 99.4%. Now, take the minimum
attack card A can have (64) and the maximum defense card B can have
(15) and use our equation. The result is 87.7%.

So, in our example, if you don't know the values of the cards fighting
it out, card A will have a 88-100% chance of beating card B if it
is attacking.

If you played card A, good job. You would have won the card battle,
but you had a 6% chance of losing, and lost. Your opponent now
controls both cards. If you had won, you'd control both cards.

In conclusion: What were they thinking?